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377. Combination Sum IV
阅读量:254 次
发布时间:2019-03-01

本文共 995 字,大约阅读时间需要 3 分钟。

Given an integer array with all positive numbers and no duplicates, find the number of possible combinations that add up to a positive integer target.

Example:

nums = [1, 2, 3]

target = 4

The possible combination ways are:

(1, 1, 1, 1)
(1, 1, 2)
(1, 2, 1)
(1, 3)
(2, 1, 1)
(2, 2)
(3, 1)

Note that different sequences are counted as different combinations.

Therefore the output is 7.

来源:力扣(LeetCode)

链接:https://leetcode-cn.com/problems/combination-sum-iv
著作权归领扣网络所有。商业转载请联系官方授权,非商业转载请注明出处。

dp[i]表示和为i的数量,4,则为单个数字,加上其他的组合数

class Solution {    public int combinationSum4(int[] nums, int target) {        int[]dp = new int[target + 1];        Arrays.sort(nums);        dp[0] = 1;        for (int i = 1; i <= target; i++) {            int num = 0;            for (int j = 0; j < nums.length; j++) {                if (nums[j] <= i) {                    num += dp[i - nums[j]];                } else break;            }            dp[i] = Math.max(dp[i], num);        }        return dp[target];    }}

 

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